On mixing `10 mL` of acetone with `40 mL` of chloroform,the total volume of the solution is

Answer

`lt80ml`.

Explanation

Chloroform `&` acetone form a non-ideal solution, in which `A.....B` type interaction are more than `A.....A & B.....B` type interaction due to `H-`bonding. Hence, the solution shows, negative deviation from Raoult's Law `i.e`.,

`DeltaV_("mix")=-ve , DeltaH_("mix")=-ve`
total volume of solution `=` less than `(30+50 ml)`
or `lt80ml`