Dry air was passed through bulbs containing a solution of `40` grams of non electrolytic solute in `360` grams of water, then through bulbs containing pure water at the same temperature and finally through a tube in which pumice moistened with strong `H_(2)SO_(4)` was kept. The water bulbs lost `0.0870` grams and the sulphuric acid tube gained `2.175` grams. Calculate the molecular weight of solute.

Answer

`M=48`

Explanation

`(P-P_(s))/(P)=(0.087)/(2.175)= ((40)/(M))/((40)/(M)+(360)/(18))`
`rArr (2.175)/(0.087)=1+(360)/(18)xx(M)/(40)`
`rArr25=1+(M)/(2)`