We have 100 mL of 0.1 MKCI solution . To make it 0.2 M

Options

A. evaporate `50mL` water
B. evaporate `50mL` solution
C. add `0.1` mol `KCl`
D. add `0.01` mol `KCl`

Answer

A, B, D

Explanation

Initial moles of `KCl=(100)/(1000)xx0.1=0.01`
Let `x` moles of `KCl` are added, so
`0.2=(0.001+x)/(100//1000)` or `x=0.01`