Two liquids `A` and `B` have `P_(A)^(@)` and `P_(B)^(@)` in the ratio of `1:3` and the ratio of number of moles of `A` and `B` in liquid phase are `1:3` then mole fraction of `A` in vapour phase in equilibrium with the solution is equal to :

Options

A. `0.1`
B. `0.2`
C. `0.5`
D. `1.0`

Answer

A

Explanation

`x_(A)=(1)(1+3)rArr(1)/(4) , x_(B)=(3)/(4) ,`
`(y_(A))/(y_(B))=(P_(A)^(@))/(P_(B)^(@))xx(x_(A)).(x_(B))`
`(y_(A))/((1-y_(A)))=(1)/(3)xx(1)/(3)`
`rArr (1)/(9)` or `y_(A)=(1)/(10)`