One mole of a solute `A` is dissolved in a given volume of solvent. The association of the solute take place as follows: `nAhArrA_(n)`
If `alpha` is the degree of association of `A,` the van't Hoff factor `i` is expressed as:

Options

A. `i=1-alpha`
B. `i=1+(alpha)/(n)`
C. `i=(1-alpha+(alpha)/(n))/(1)`
D. `i=1`

Answer

C

Explanation

`i=(C(1-alpha)+(Calpha)/(n))/(C) rArri=1 - alpha +(alpha)/(n)`