If `M_("normal")` is the normal molecular mass and `alpha` is the degree of ionization of `K_(3)[Fe(CN)_(6)]`, then the abnormal molecular mass of the complex in the solution will be :

Options

A. `M_("normal")`
B. `M_("normal")(1+3alpha)^(-1)`
C. `M_("normal")(1+alpha)^(-1)`
D. equal to `M_("normal")`

Answer

B

Explanation

`{:(,K_(3)[Fe(CN)_(6)],hArr,3K^(+),+,[Fe(CN)_(6)]^(3-)),(At t=0,1,,0,,0),("After ionization",(1-alpha),,3alpha,,alpha,i=1+3alpha):}`
Since, `i=(M("normal"))/(M_("normal"))`
`therefore (1+3alpha)/(1)=(M_("normal"))/(M_("abnormal"))`