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PtCl(4).6H(2)O can exist as a hydrated c...

`PtCl_(4).6H_(2)O` can exist as a hydrated complex. `1 m` aqueous solution has the depression in freezing point of `3.72^(@)`. Assume `100%` ionization and `K_(f)(H_(2)O)=1.86^(@)mol^(-1) kg`, then the complex is

A

`[Pt(H_(2)O)_(6)]Cl_(4)`

B

`[Pt(H_(2)O)_(4)Cl_(3)Cl_(2).2H_(2)O`

C

`[Pt(H_(2)O)_(3)]Cl.3H_(2)O`

D

`[Pt(H_(2)O)_(2)Cl_(4)].4H_(2)O`

Text Solution

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The correct Answer is:
C
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PtCl_(4). 6H_(2)O can exist as hydrated complex 1 molal aq. Solution has depression in freezing point of 3.72^(@) . Assume 100% ionisation and K_(f)(H_(2)O) = 1.86^(@) mol^(-1) kg , then complex is :

PtCl_(4).6H_(2)O can exist as hydrated complex 1 molal aq.solution has depression in freezing point of 3.72^(@)C Assume 100% ionisation and K_(f)(H_(2)O=1.86^(@)mol^(-1))kg then complex is

Compound PdCl_(4).6H_(2)O is a hydrated complex, 1 m aqueous solution of it has freezing point 269.28 K . Assuming 100% ionization of complex, calculate the number of ions furnished by complex in the solution.

Compound PdCl_(4). 6H_(2)O is a hydrated complex, 1 molal aqueous solution of it has freezing point 269.28 K. Assuming 100% ionization of complex, calculate the molecular formula of the complex ( K_(f) for water = 1.86 K mol^(-1) )

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