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Two unequal masses, m1 = 2m and m2 = m h...

Two unequal masses, `m_1 = 2m` and `m_2 = m` have unequal positive charge on them. They are suspended by two mass-less threads of unequal lengths from a common point such that, in equilibrium, both the masses are on same horizontal level. The angle between the two strings is `theta=45^(@)` in this position. Find the Electrostatic force applied by `m_1` on `m_2` in this position.

Text Solution

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The correct Answer is:
`((sqrt(17)-3)/(2))mg`
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Knowledge Check

  • Two small balls, each having equal positive charge Q are suspended by two insulationg strings of equal length l from a hook fixed to a stand. It mass of each ball =m and total angle between the two strings is 60^(@) m, then find the charge on each ball.

    A
    `sqrt((mg)/(4piepsilon_(0)l^(2)))`
    B
    `sqrt(2piepsilon_(0)l^(2)mg)`
    C
    `sqrt((piepsilon_(0)l^(2)mg)/(4)`
    D
    `sqrt((4piepsilon_(0)l^(2)mg)/(sqrt3)`

  • A uniform rod of mass m and length L is suspended with two massless strings as shown in the figure. If the rod is at rest in a horizontal position the ratio of tension in the two strings T_1/T_2 is:

    A
    `1:1`
    B
    `1:2`
    C
    `2:1`
    D
    `4:3`

  • Two masses m and M are attached to the strings as shown in the figure. If the system is in equilibrium, then

    A
    `tantheta=1+(2M)/(m)`
    B
    `tantheta=1+(2m)/(M)`
    C
    `cottheta=1+(2M)/(m)`
    D
    `cottheta=1+(2m)/(M)`

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