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A short bar magnet having magnetic dipol...

A short bar magnet having magnetic dipole moment M is moving along the axis of a fixed conducting (non magnetic) ring of radius R. The axis of the ring is along z direction.

(a) Write the z component of magnetic field due to the magnetic dipole at a point P in the plane of the ring, at the instant the magnet is at a distance z from the centre of the ring. Position of point P can be defined in terms of angle `theta` as shown.
(b) Write the magnetic flux through the ring due to the magnetic field produced by the magnet as a function of z.
(c) Write the magnitude of emf induced in the ring at the instant shown if speed of the magnet at the moment is v.

Text Solution

Verified by Experts

The correct Answer is:
(a) `b_(z)=(mu_(0))/(4pir^(3))[2 cos^(2) theta -sin^(2)theta]`
(b) `phi=(mu_(0)MR^(2))/(2(R^(2)+z^(2))^(3//2))`
(c) `E_("in")=(3mu_(0)MR^(2)vz)/(2(R^(2)+z^(2))^(5//2))`
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Knowledge Check

  • The magnetic field due to a short magnet at a point in its axis at distance X cm from the middle of the magnet is

    A
    `100` Gauss
    B
    `400` Gauss
    C
    `50` Gauss
    D
    `200` Gauss
  • The magnetic field due to short bar magnet of magnetic dipole moment M and length 21, on the axis at a distance z (where zgtgtI ) from the centre of the magnet is given by formula

    A
    `(mu_(0)M)/(4piz^(3))T`
    B
    `(2mu_(0)M)/(4piz^(3))T`
    C
    `(4mu_(0)M)/(piz^(3))T`
    D
    `(mu_(0)M)/(2piz^(3))T`
  • A bar magnet of length l and magnet dipole moment M is bent in the form of an arc. The new magnetic dipole moment is

    A
    `3/piM`
    B
    `2/piM`
    C
    `M/2`
    D
    M
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