Home
Class 12
CHEMISTRY
Calculate the % ionic character of molec...

Calculate the % ionic character of molecules AB where the electronegative atom A is 3 and B is 2.1 ?

A

`17.2%`

B

`19%`

C

`34%`

D

`50%`

Text Solution

Verified by Experts

The correct Answer is:
1

% ionic character
`=16|3-2.1|+3.5|3-2.1|^(2)`
=17.2%
Promotional Banner

Topper's Solved these Questions

Similar Questions

Explore conceptually related problems

Calculate the % ionic character for molecule AB when E.N. different is 2.0:

Calculate the % ionic character for metal fluoride where the electronegativity of electropositive element is 2.1:

Calculate the percentage of ionic character in Cs-Cl bond in CsCl molecule. The electronegativity values of CS and Cl are 0.7 and 0.3 respectively.

Calculate the percentage ionic and covalent character of HF molecule having bond distance =0.92Å and dipole moment =1.78D

A polar covalent bond shows 50% ionic character. What should be the electronegativity difference of the atoms that form a polar covalent bond?

What is the effect of more electronegative atoms on the strength of an ionic bond ?

The percentage ionic characterin Cs-Cl bond present in CsCl molecule will, be, if the electronegativities for Cs and Cl are 0.8 and 3.0 , respectively

The percentage ionic character in a compound AB if inter nuclear distance between A and B is 127pm and its dipole moment is 2.06D