Calculate total number of `SO_(2)` molcules in a sample having 32 miligrams of the `SO_(2)` gas, `1.4xx10^(20)` number of `SO_(2)` molcules, 0.8 ml of `SO_(2)` gas at 6 atm & 300 K. [Given `N_(A)=6xx10^(23)`,R=0.08 atm lit/mol K]
[Express your answer in terms of multiple of `10^(20)` and then round off to nearest integer for e.g. if your answer is `6.2 xx10^(20)` fill 6 in OMR after rounding off.]

Answer

6

Explanation

Total number of molecules `=(32/64xx10^(-3)xx6xx10^(23)+1.4xx10^(20)+(6xx0.8)/(1000xx0.0821xx300)xx6xx10^(23)))`
`=(0.5xx6xx10^(20)+1.4xx10^(20)+1.16xx10^(20))`
`(1.4+3+1.16)xx10^(20)~~ 5.6xx10^(20) ~~6xx10^(20)`