Two different formulas are used in order to represent composition of any miolecule, empirical formula and molecular formula . While the fomer gives an idea of relative ratio of number of atoms, latter gives the exact number of atoms in the molecule.
4.6 gm of an organic compound on complete combustion gave 8.8 gm of `CO_(2)(g)` and 5.4 gm of `H_(2)O(g)` only and no other products . what will be the empirical formula of the hydrocarbon?

Options

A. `CH_(3)`
B. `C_(2)H_(6)O`
C. `CH_(2)O`
D. `CH_(2)`

Answer

A or B

Explanation

`{:(C_(2)H_(6)O,+3O_(2) to ,2CO_(2)(g),+3H_(2)O),("0.1 mole","0.2 mole","0.3 mole"):}`