A particular elements 'X' can be found in three gaseous forms -mono-atomic, di-atomic and tri-atomic. If density of one of its from at a pressure of 8.21 atm at 400 K is 18 gm/lit, then what would be atomic mass of the element

Options

A. 72
B. 24
C. 36
D. 144

Answer

ABC

Explanation

PM=dRT
`M=(dRT)/P=(18xx0.0821xx400)/8.21 =72 `
Atomic masses can be =`72/1=72`
for diatomic =`72/2=36`
for triatomic `=72/3=24`