A sample of oxygen atoms contain only `._(8)O^(16)` and `._(8)O^(18)` isotopes. If the average atomic mass of the sample is 16.8, then identify the options which is/are correct ?

Options

A. mass % of `O^(16)` is less then 60 %
B. mole % of `O^(18)` is 40%
C. average number of neutron/atom is equal to 8.8
D. average number of neutron/proton is equal to 1.1

Answer

ABCD

Explanation

`{:(._(8)OO^(16),:,._(8)O^(18)),(x,:,100-x),(60,:,40):}`
`M_(avg.) =16.8=(xxx15+18(100-x))/100`
x=60
Average number of neutron `=(8xx6+16xx4)/10 =8.8`
Average number of proton =8
`=n/p=8.8/8=1.1`