A sample of clay contains 60% Silica & 15 % water. The sample is heated such that the partially dried sample contains 66% Silica. What will be % of water in partially dries sample ?

Options

A. 0.1
B. 0.065
C. 0.12
D. 0.14

Answer

2

Explanation

Support sample is 100 gm
`(W_(si))/(W_("sample"))xx100=66`
`(60xx100)/66=w_("sample")`
`90.9 =w_("sample")`
water left =15-9.1=5.9 gm
% of water `5.9/90.9xx100=6.5%`