For a sequential reaction
`NH_(3)to N_(2)+H_(2)....(i)`
`H_(2)+O_(2) to H_(2)O......(ii)`
What will be the amount of water which will be obtained if 5 moles of `NH_(3)` is mixed with 3 moles of `O_(2)` & % yeild of `1^(st) & 2^(nd)` reaction is 50% & 80 % respectively.

Options

A. 3 moles
B. 2.5 moles
C. 2 moles
D. 2.4 moles

Answer

1

Explanation

`{:(2NH_(3),overset(50%)to,N_(2)(g),+,3H_(2)(g)),("5 mole",,(5/2 "mole")/2,,(3/2xx5"mole")/2),(H_(2)(g),+,1/2O_(2)(g),overset(80%)to,H_(2)O(l)),(3.75 "mole",,"3mole (LR)",,3.75xx0.8=3" mole"):}`