200 gm of an oelum sample (labelled as 109`%`) is mixed with 400 gm of another oleum sample (labelled as 118`%`). The labelling of the new sample formed will be :

Options

A. 1.15
B. 1.12
C. 1.22
D. 1.16

Answer

A

Explanation

`{:(SO_(3),+,H_(2)O to ),(400,,),(5,,5xx18=90 gm):}`
For 100 gm sample `=100+90/6 =115%`