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A particle of e/m ratio equal to 4xx10^(...

A particle of `e/m` ratio equal to `4xx10^(5)` coul/kg is accelerated from rest through a potential difference of 20 Volt. The speed of particles is

A

4.0 m/s

B

4000 km/s

C

4000 cm/s

D

4000 m/s

Text Solution

Verified by Experts

The correct Answer is:
4
`KE=qV=1/2 mV^(2)`
`q/m=1/2 (V^(2))/V`
`V^(2)=2xxq/mxxV=2xx4xx10^(5) xx20 `
`" " 40xx4xx10^(15) =16xx10^(6)`
`V=4xx10^(3) m//sec`.
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