Find the maximum number of identical bond angles in `CH_(2)F_(2)`.

Explanation

To find the maximum number of identical bond angles in CH₂F₂, we can follow these steps:

### Step 1: Determine the molecular structure of CH₂F₂
- Carbon (C) is the central atom, and it is bonded to two hydrogen (H) atoms and two fluorine (F) atoms.
- The molecular formula indicates that there are four substituents around the carbon atom.

### Step 2: Draw the Lewis structure
- Start by placing the carbon atom in the center.
- Attach two hydrogen atoms and two fluorine atoms to the carbon atom.
- The structure can be represented as:
```
F
|
H - C - F
|
H
```

### Step 3: Identify the geometry of the molecule
- The carbon atom has four substituents (two H and two F), which means it adopts a tetrahedral geometry according to VSEPR theory.

### Step 4: Analyze the bond angles
- In a tetrahedral structure, the ideal bond angles are 109.5 degrees.
- However, due to the presence of different atoms (H and F), the bond angles will vary slightly.

### Step 5: Identify identical bond angles
- The bond angles between the fluorine atoms and the carbon (F-C-F) are identical.
- The bond angles between the hydrogen atoms and the carbon (H-C-H) are also identical.
- The bond angles between the fluorine and hydrogen atoms (F-C-H) will be different from the F-C-F and H-C-H angles.

### Step 6: Count the identical bond angles
- There are two identical bond angles for F-C-F (let's call this angle 1).
- There are two identical bond angles for H-C-H (let's call this angle 2).
- Therefore, the maximum number of identical bond angles in CH₂F₂ is 4.

### Final Answer
- The maximum number of identical bond angles in CH₂F₂ is **4**.

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