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The Schrodinger wave equation for hydrog...

The Schrodinger wave equation for hydrogen atom is ` psi_(2s) =1/(4sqrt(2pi)) (1/(a_(0)))^(3//2)(2-r/(a_(0)))e^(-t//a_(0))`
where `a_0` is Bohr's radius. If the radial node in 2 s be at `r_0`, then `r_0` would be equal to

A

`(a_(0))/2`

B

`2a_(0)`

C

`sqrt(2)a_(0)`

D

`(a_(0))/(sqrt(2))`

Text Solution

Verified by Experts

The correct Answer is:
2
`2-r/(a_(0)) =0 ` at radial node
`r=2a_(0)`
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