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An alpha- particle accelerated through V...

An `alpha`- particle accelerated through V volt is fired towards a nucleus. It distance of closest approach is r. If a proton accelerated through the same potential is fired towards the same nucleus, the distance of closest approach of the proton will be :

A

r

B

2r

C

`r/2`

D

`r/4`

Text Solution

Verified by Experts

The correct Answer is:
1
`a_(alpha)=+2e`
`2eV=(Kxx(2e)(Ze))/r`
`eV=(Kxx(e)(Ze))/x`
x=r
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