A hydrogen like species with atomic number Z is present in a higher excited state (n) . This electron can make transition to the first excited level by successively emitting two photons of energy 2.64 eV and 48.36 eV . This electron can also make transition to third excited state by emitting three photons of energy 2.64 eV , 2. 66 eV and 4.9 eV .
Identify the hydrogen like species involved .

Options

A. `He^(+)`
B. `Li^(+2)`
C. `Be^(+3)`
D. `B^(+4)`

Answer

3

Explanation

`2.64+48.36 =13.6 xxZ^(2)(1/(2^(2))-1/(n^(2)))`
`2.64+2.66+4.9=13.6 xxZ^(2)(1/(4^(2))-1/(n^(2)))`
`Z=4` and n=8