A container with a volume of 20.0 L holds `N_(2(g))` and `H_(2)O_((l))` at 300 K and 1.0 atm. The liquid water is then decomposed completely into `H_(2(g))` and `O_(2(g))` by any means, at constant temperature, if the final pressure becomes 1.86 atm, what was the mass of water (jn gm) present initially. Neglect the initial volume of water: [Given : vapour pressure of water at 300 K=0.04 atm L-atm / K -mol]

Answer

2

Explanation

`P_(gas)=1-0.04 =0.96 gm`
`{:(H_(2)O_((l)) hArr,H_(2(g)),+,1/2 O_(2(g))),("x=0.5 mole",x,,x/2" "=3/2 x =1.86 -0.96 =0.9),(=9gm,,,),(0.9xx20=3/2x xx24,,,x=0.6),(0.5=12/24 =x,,,):}`