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Calculate pressure (in atm) of a Vander-waal gas taken at temperature of 399K if its density is equal to `12gm//L`. Given : `a= 6.4 atm-litre^2 mol^(-2)` and `b=0.01 L mol^(-1)` molar mass = 48, R=0.0821 `atm-L mol^(-1) K^(-1)`

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The correct Answer is:
8
`(P-a/(V_(m^(2))))(V_(m)-b)=RT " " d=M/V`
`(P-6.4/42)(4-0.01)0.0821 xx 399 " " 12=48/V`
`P=781 atm " " V=4L`
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