If the ratio of lengths, radii and youngs's modulus of steel and and brass wires in figure are 2:1,2:1,3:1 respectively. Then corresponding ratio of increases in their would be. (Neglect the mass of the wire and take `g=10m//s^(2)`)

Options

A. `1:4`
B. `8:1`
C. `1:3`
D. `2:4`

Answer

A

Explanation

`T=YA (Deltal)/l`
`rArr Deltal =(Tl)/(YA)`
`(Deltal_(1))/(Deltal_(2)) =(T_(1))/(T_(2))xx(l_(1))/(l_(2)) xx(Y_(2))/(Y_(1))xx(A_(2))/(A_(1))`
`=(3mug)/(2 mug)xx2/1 xx1/3xx1/4 =1:4`