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As per KTG, molecules in gaseous state a...

As per KTG, molecules in gaseous state are under continuous motion with no intermolecular forces occurring & the speed of the molecules will keep on changing due to the molecular collections. The distribution pattern remains constant and is given by `(dN)/(du) = 4 pi N (M/(2 pi R T))^(3/2) u^2 . e^((-Mu^2)/(2RT))` (symbols have usual meaning). The collisions are assumed to be perfectly elastic. In case there are more than one gas in the container then also presence of one type of gas will not affect movement of other gas than one gas. Based on this information, answer the question that follows.
A container consist of two gases `O_2` & `SO_2`. Assuming them to be non reactive & behaving ideally identify the correct statement.

A

Each molecule of `O_(2)` will cause lesser change in momentum due to wall collision as compared to `SO_(2(g))`

B

Average relative speed of approach of `O_(2)` and `SO_(2)` molecule will be `sqrt((3RT)/(8pi))`

C

`O_(2(g))` will exert higher pressure irrespective of the amount taken.

D

Average translational kinetic energy of mole of `SO_(2)` nad `O_(2` will be different.

Text Solution

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The correct Answer is:
B
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