An unspecified quantity of an ideal gas was at initial pressure of 5 atm and temperature of 300K. The gas is expanded at 300K until the volume has increased by 60% of the initial value. Next, the quantity of the gas in the vessel is increased by 20% of the initial value while the volume is maintained constant. Finally, the temperature is adjusted at constant volume until the gas pressure is again 5 atm. If the final temperature is 'T'K, then the value of `T/(100)` is

Answer

4

Explanation

`P_(1)=5atm`
`T_(1)=300 k`
`P_(1)V_(1)=P_(2)V_(2)`
`5xx100=P_(2) xx160`
`P_(2)=500/160 atm " " T_(2)=300 K`
`P_(3)=1.2 xx500/160 atm " " T_(3) =300 K`
`(P_(3))/(T_(3))=(P_(4))/(T_(4))`
`((1.2xx5xx100)/160)/300=5/T`
`T=(300xx16)/(10xx1.2)=400 K`
Ans 4.