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Kalpha wavelength emitted by an atom of ...

`K_alpha` wavelength emitted by an atom of atomic number Z=11 is `lambda`. Find the atomic number for an atom that emits `K_alpha` radiation with wavelength `4lambda`.
(a) Z=6 (b) Z=4
(c ) Z=11 (d) Z=44.

A

6

B

4

C

8

D

14

Text Solution

Verified by Experts

The correct Answer is:
A
`sqrt(v)=a(z-1)`
`(1)/(sqrt(v))=a'(z-1)`
`(1)/(sqrt(v))=a(11-1)" "(1)/(sqrt(4v))=a'(z-1)`
So, `(10)/(z-1)=2impliesz=6`
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