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A circular current carrying loop of radi...

A circular current carrying loop of radius R, carries a current l. The magnetic field at a point on the axis of coll is `(1)/(sqrt(8))` times the value of magnetic field at the centre. Distance of point from centre is

A

`(R )/(sqrt(2))`

B

`(R )/(sqrt(3))`

C

`Rsqrt(2)`

D

R

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AI Generated Solution

To solve the problem, we need to find the distance from the center of a circular current-carrying loop to a point on its axis where the magnetic field is \( \frac{1}{\sqrt{8}} \) times the magnetic field at the center of the loop. ### Step-by-Step Solution: 1. **Magnetic Field at the Center of the Loop**: The magnetic field \( B_c \) at the center of a circular loop of radius \( R \) carrying a current \( I \) is given by the formula: \[ B_c = \frac{\mu_0 I}{2R} ...
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