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A circular current carrying loop of radi...

A circular current carrying loop of radius R, carries a current l. The magnetic field at a point on the axis of coll is `(1)/(sqrt(8))` times the value of magnetic field at the centre. Distance of point from centre is

A

`(R )/(sqrt(2))`

B

`(R )/(sqrt(3))`

C

`Rsqrt(2)`

D

R

Text Solution

AI Generated Solution

To solve the problem, we need to find the distance from the center of a circular current-carrying loop to a point on its axis where the magnetic field is \( \frac{1}{\sqrt{8}} \) times the magnetic field at the center of the loop. ### Step-by-Step Solution: 1. **Magnetic Field at the Center of the Loop**: The magnetic field \( B_c \) at the center of a circular loop of radius \( R \) carrying a current \( I \) is given by the formula: \[ B_c = \frac{\mu_0 I}{2R} ...
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  • A square loop of edge 'a' carries a current l. The magnetic field at the centre of loop is

    A
    `(mu_(0)l)/(2 sqrt2 pi a)`
    B
    `(2sqrt2 mu_(0)l)/(pi a)`
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  • A square loop of side a carris a current I . The magnetic field at the centre of the loop is

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    B
    `(mu_0Isqrt2)/(pia)`
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    `(4mu_0Isqrt2)/(pia)`
    D
    `(mu_0I)/(pia)`
  • A square conducting loop of side length L carries a current I.The magnetic field at the centre of the loop is

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    independent of L
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    proportional L
    C
    inversely proportional to L
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