Hydrogen `(_(1)H^(1))` Deuterium `(_(1)H^(2))` singly omised helium `(_(1)He^(1))` and doubly ionised lithium `(_(1)Li^(6))^(++)` all have one electron around the nucleus Consider an electron transition from `n = 2 to n = 1` if the wavelength of emitted radiartion are `lambda_(1),lambda_(2), lambda_(3),and lambda_(4)`, repectivelly then approximetely which one of the following is correct ?

Options

A. `lambda_(1)=lambda_(2)=4lambda_(3)=9lambda_(4)`
B. `4lambda_(1)=2lambda_(2)=2lambda_(3)=lambda_(4)`
C. `lambda_(1)=2lambda_(2)=2sqrt(2)lambda_(3)=3sqrt(2)lambda_(4)`
D. `lambda_(1)=lambda_(2)=2lambda_(3)=3lambda_(4)`

Answer

A

Explanation

`(1)/(lambda)=R((1)/(1)-(1)/(4))z^(2)`
`lambda_(1):lambda_(2):lambda_(3):lambda_(4)=1:1:(1)/(4):(1)/(9)`
`lambda_(1)=lambda_(2)=4lambda_(3)=9lambda_(4)`