Ring of mass M and radius 1m placed on smooth horizontal surface at rest. A particle of same mass M moving horizontally with speed `6 m//s` strike the ring and stick to it as shown in figure. Find angular speed of system after collision in rad/sec.

Answer

2

Explanation

Conservation of angular momentum. About Point P.
`M(6)((R)/(2))=[(MR^(2))/(2)+M((R)/(2))^(2)+M((R)/(2))^(2)]omega`
`3MR = [MR^(2)]omega`
`omega=(3)/(R)=3"rad"//"sec"`