If 1 - p is a root of the quadratic equation `x^(2) + px + 1- p = 0` , then its roots are

Options

A. `0,-1`
B. `-1,1`
C. `0,1`
D. `-1,2`

Answer

D

Explanation

`LHL = underset(xrarro^(-))(Lim)(x)/(ln(1+x)).[x]^(2)ln2=ln2`
`RHL = underset(xrarr0^(+))(Lim)(ln(e^(x^(2))+2sqrt(x)))/(sqrt(x)((tansqrt(x))/(sqrt(x))))=underset(xrarr0^(+))(Lim)(lne^(x^(2))+ln(1+(2sqrt(x))/(e^(x^(2)))))/(sqrt(x))`
`=underset(xrarr0^(+))(Lim)(x^(2))/(sqrt(x))+ln(1+(2sqrt(x))/(e^(x^(2))))/((2sqrt(x))/(e^(x^(2))))x(2)/(e^(x^(2)))=2impliesLHL ne RHL `