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Let A =[(1,1,0),(0,1,0),(0,0,1)] and let...

Let A =`[(1,1,0),(0,1,0),(0,0,1)]` and let I denote the `3xx3` identity matrix . Then `2A^(2) -A^(3)` =

A

`A+1`

B

`A-1`

C

`l-A`

D

A

Text Solution

Verified by Experts

The correct Answer is:
B
`underset(Lrarr0)(Lt)[(x)/(sinx)]=1" and "underset(xrarr0)(Lt)[(sin^(-1)(x))/(x)]=1 " and "underset(xrarr0)(Lt)[(tan^(-1)x)/(x)]=0`
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