Two bodies begin to fall freely from the same height but the second falls T second after the first. The time (after which the first body begins to fall) when the distance between the bodies equals L is

Options

A. `(T)/(2)`
B. `(T)/(2)+(L)/(gT)`
C. `(L)/(gT)`
D. `T+(2L)/(gT)`

Answer

D

Explanation

`alpha=(T_(1)-T_(2))/(T_(1))" and "beta=(T_(2))/(T_(1)-T_(2)),alphabeta=(T_(2))/(T_(1))`