If `y=ax^(2)+bx+c` is the reflection of parabola `y=x^(2)-4x+1` about the line `y=3,a+b+c=`

Options

A. 1
B. 2
C. 3
D. 4

Answer

B

Explanation

`sqrt((x+3)(x-2))-(x-2)=sqrt((x-2)(x-5))`
For the equation to be defined
`x in (-oo,-3] uu [2,oo)" and "x in (-oo,2]uu[5,oo)`
`therefore x in (-oo,-3]uu[5,oo)uu{2}`
On solving we get `x=2,6,-(10)/(3)`