A transverse wave is derscried by the equation `y=y_(0) sin 2 pi (ft - (x)/(lamda))`. The maximum particle velocity is equal to four times the wave velocity if :-

Options

A. `lambda=(piy_(0))/(4)`
B. `lambda=(piy_(0))/(4)`
C. `lambda=piy_(0)`
D. `lambda=2piy_(0)`

Answer

A

Explanation

`(1)/(R_(eq))=(1)/(3R)+(2)/(3R)+(1)/(R)`
`=(1+2+3)/(3R)=(2)/(R)`
`impliesR_(eq)=(R)/(2)`