At what temperature the molecule of nitrogen will have same rms velocity as the molecule of oxygen at `127^(@)C` ?

Options

A. `77^(@)C`
B. `350^(@)C`
C. `273^(@)C`
D. `457^(@)C`

Answer

D

Explanation

`a=2+|t-2|`
For `tle2`
`a=2-t+2=4-t`
`i.e. dv =(4-t)dt" ""or"" "v=4t-t^(2)//2`
At `t = 2, v = 6 m//s`
For `t gt 2`
`a = 2 + t - 2 = t`
`i.e.underset(6)overset(v)intdv=underset(2)overset(t)inttdt" or "v-6=[t^(2)//2]_(2)^(1)" or "v=(t^(2))/(2)+4`
At `t=4,v=12m//s`