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A particle is projected form a horizonta...

A particle is projected form a horizontal plane `(x-z` plane) such that its velocity vector at time `t` is gives by `vecV = ahati +(b - ct)hatj`. Its range on the horizontal plane is given by

A

`(ba)/c`

B

`(2ba)/c`

C

`(3ba)/c`

D

None

Text Solution

Verified by Experts

The correct Answer is:
B
`vec(v)=ahat(i)+(b-ct)hat(j)`
Time to reach maximum height (when `hat(j)` comp. of velocity becomes zero)
`:. B-ct=0rArr t=b/c :.` Time of fight `=(2b)/c`
range= horizontal velocity `xx` Time of flight `=axx(2b)/c`
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