If acceleration of M is a then acceleration of m is

Options

A. `3a`
B. `a/3`
C. a
D. `sqrt(10)a`

Answer

D

Explanation

Net tension on M
`equiv sqrt((3T)^(2)+T^(2))=sqrt(10)T`

Now from acceleration`xx` Tension = constant
`rArr a_(M)(sqrt(10)T)=a_(m)(T)rArr a_(m)(sqrt(10))a_(M)=sqrt(10)a`
OR
Net acceleration of m
`equiv sqrt(a^(2)+(3a)^(2))=sqrt(10)a`