For a body in circular motion with a constant angular velocity, the magnitude of the average acceleration over a period of half a revolution is … times the magnitude of its instantaneous acceleration.

Options

A. `2/pi`
B. `pi/2`
C. `pi`
D. `2`

Answer

A

Explanation

`omega=` constant, `a_(T)=0`
`[(2omega^(2)rx)/pi, omega=(2pi)/T, T/2=pi/omega]`
`a_(av)=(2omegaR)/(pi//omega)=(2omega^(2)R)/pi, a_("inst")=omega^(2)R`
So radio `=a_(av)/a_("inst")=2/pi`