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A particle is projected from a point P(2...

A particle is projected from a point `P(2, 0, 0)m` with a velocity `10 m//s` making an angle `45^(@)` with the horizontal. The plane of projectile motion passes through a horizontal line PQ which an angle of `37^(@)` with positive x-axis, xy plane is horizontal. The coordinates of the point where the particle will strike the line PQ is :- `("take "g=10 m//s^(2))`

A

`(10, 6, 0) m`

B

`(8, 6, 0)m`

C

`(10, 8, 0) m`

D

`(6, 10, 0)m`

Text Solution

Verified by Experts

The correct Answer is:
A
`PQ=R=(u^(2) sin 90^(@))/(g)=(100xx1)/(10)=10 rArr PQ=10`

`(x,y)=(10, 6, 0)`
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