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Statement-I : A projectile is thrown wit...

Statement-I : A projectile is thrown with an initial velocity of `(ahat(i)+bhat(j)) m//s`. If range of projectile is maximum then `a=b`.
Statement-II : In projectile motion, angle of projection is equal to `45^(@)` for maximum range condition.

A

Statement-I is true, Statement-II is true, Statement-II is correct explanation for Statement-I

B

Statement-I is true, Statement-II is true, Statement-II is NOT a correct explanation for Statement-I

C

Statement-I is true, Statement-II is false

D

Statement-I is false, Statement-II is true.

Text Solution

Verified by Experts

The correct Answer is:
A
For max. range `((u^(2) sin 2theta)/g)`, the projection angle `(theta)` should be `45^(@)`
So initial velocity `ai+bjrArr tan 45^(@)=b/arArr a=b`
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Knowledge Check

  • A projectile is thrown with an initial velocity of (a hati + hatj) ms^(-1) . If the range of the projectile is twice the maximum height reached by it, then

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