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The velocity- time graph of the particle...

The velocity- time graph of the particle moving along a straight line is shown. The rate of acceleration and deceleration is constant and it is equal to `5 ms^(-2)`. If the average velocity during the motion is `20 ms^(-1)`, then the value of t is

A

`3` sec

B

`5` sec

C

`10` sec

D

`12` sec

Text Solution

Verified by Experts

The correct Answer is:
B
Average velocity
`=("Displacement")/("time interval")=("Area under v-t curve")/("time")`

`20=(1/2[25+25-2t]xx5t)/25rArr t=5, 20`
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