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In the figure shown, acceleration of 1 i...

In the figure shown, acceleration of 1 is x (upwards). Acceleration of pulley `P_(3)`, w.r.t. pulley `P_(2)` is y (downwards) and acceleration of 4 w.r.t. to pulley `P_(3)` is z (upwards). Taking upward +ve and downward -ve then

`{:(,"Column I",,,"Column II"),((A),"Absolute acceleration of 2",,(p),(y-x) "downwards"),((B),"Absolute acceleration of 3",,(q),(z-x-y) "upwards"),((C),"Absolute acceleration of 4",,(r),(x+y+z) "downwards"),(,,,(s),"None"):}`

Text Solution

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The correct Answer is:
(A)-s, (B)-r, (C)-q
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