A chemist isolated a compound A with molecular formula `C_(7)H_(13) Br`. A undergoes very fast `S_(N)1` reaction. Spectroscopic evidence indicated that compound A has the following structural characteristics.
. It contains fnive `sp_(3)` hybridised carbon atoms. Among those five `SP^(3 )` carbon atoms are three methyl groups, one `CH_(2)` group and one CH group.
. It also contains two `SP_(2)`-hybridised carbon atoms . Also there is only one hydrogen atom attched to `sp^(2)` carbons.
. The compound contains a total of six allylic hydrogen atoms.
. The carbon atom that holds the Br has one H attached to it.
When compound A reacts with boiling water , it undergoes an `S_(N)1` reaction and produces. two principal products B and C . Both B and C are alcohols with their molecular formula `C_(7)H_(14)O`. Among the two alcohols, B has the --OH group attached to an `sP_(3)` carbon atom that has no H atoms bonded to it .
What can be said about the isomerism shown by the two alcohols B and C ?

Options

A. Both B and C show stereo isomerism and can be resolved into enantiomers
B. B and C are stereoisomers
C. Both B and C show stereoisomerism but only C Can be resolved into enantiomers
D. Neither B or C can be resolved into enantiomers

Answer

C