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If cosx=(sqrt(3))/(2), find cos2x....

If `cosx=(sqrt(3))/(2)`, find cos2x.

A

`-0.87`

B

`-0.25`

C

`0`

D

0.5

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The correct Answer is:
To solve the problem where \( \cos x = \frac{\sqrt{3}}{2} \) and we need to find \( \cos 2x \), we can follow these steps: ### Step 1: Identify the formula for \( \cos 2x \) The double angle formula for cosine is given by: \[ \cos 2x = 2 \cos^2 x - 1 \] ### Step 2: Substitute the value of \( \cos x \) We know that \( \cos x = \frac{\sqrt{3}}{2} \). We will substitute this value into the formula: \[ \cos 2x = 2 \left( \frac{\sqrt{3}}{2} \right)^2 - 1 \] ### Step 3: Calculate \( \left( \frac{\sqrt{3}}{2} \right)^2 \) Calculating the square: \[ \left( \frac{\sqrt{3}}{2} \right)^2 = \frac{3}{4} \] ### Step 4: Substitute back into the formula Now substitute \( \frac{3}{4} \) back into the equation: \[ \cos 2x = 2 \left( \frac{3}{4} \right) - 1 \] ### Step 5: Simplify the expression Calculating \( 2 \left( \frac{3}{4} \right) \): \[ 2 \left( \frac{3}{4} \right) = \frac{6}{4} = \frac{3}{2} \] Now substituting this back into the equation: \[ \cos 2x = \frac{3}{2} - 1 \] ### Step 6: Convert 1 into a fraction To subtract, convert 1 into a fraction with the same denominator: \[ 1 = \frac{2}{2} \] So, \[ \cos 2x = \frac{3}{2} - \frac{2}{2} = \frac{1}{2} \] ### Step 7: Final answer Thus, we find: \[ \cos 2x = \frac{1}{2} \] ### Conclusion The value of \( \cos 2x \) is \( \frac{1}{2} \), which corresponds to option d.

To solve the problem where \( \cos x = \frac{\sqrt{3}}{2} \) and we need to find \( \cos 2x \), we can follow these steps: ### Step 1: Identify the formula for \( \cos 2x \) The double angle formula for cosine is given by: \[ \cos 2x = 2 \cos^2 x - 1 \] ...
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