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Factorize y^2+6y+8 by using the method o...

Factorize `y^2+6y+8` by using the method of completing the square.

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`y^2+6y+8`
Adding and subtracting `(6/2)^2`, i.e., `3^2`.
`=y^2+6y+8+3^2-3^2`
`=y^2+6y+9-9+8`
`=y^2+2timesytimes3+3^2-1`
`=(y+3)^2-1^2`
`=(y+3-1)(y+3+1)`
`=(y+2)(y+4)`
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