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A work force of 50 men with a contractor...

A work force of 50 men with a contractor can finish a piece of work in 5 months. In how many months the same work can be completed by 125 men?

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Let `x` be the number of days required to complete a piece of work by `125` men.
Since, the number of men and the number of days taken to do a piece of work are in inverse variation, we have:
`=> 50xx5=125x`
`=> x= (50xx5)/125`
​`therefore x=2`
`therefore` The required number of months are `2`.
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