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1, 14, 31, 64, 133, 264...

1, 14, 31, 64, 133, 264

A

14

B

31

C

264

D

133

Text Solution

AI Generated Solution

The correct Answer is:
To find the odd one out from the series: 1, 14, 31, 64, 133, 264, we will analyze the differences between the consecutive terms to identify any patterns. ### Step-by-step Solution: 1. **Identify the series**: The given series is: \[ 1, 14, 31, 64, 133, 264 \] 2. **Calculate the first differences**: We will find the differences between consecutive terms: - \(14 - 1 = 13\) - \(31 - 14 = 17\) - \(64 - 31 = 33\) - \(133 - 64 = 69\) - \(264 - 133 = 131\) So, the first differences are: \[ 13, 17, 33, 69, 131 \] 3. **Calculate the second differences**: Now, we will find the differences between the first differences: - \(17 - 13 = 4\) - \(33 - 17 = 16\) - \(69 - 33 = 36\) - \(131 - 69 = 62\) So, the second differences are: \[ 4, 16, 36, 62 \] 4. **Analyze the second differences**: The second differences do not show a consistent pattern. Let's look at the differences again: - \(16 - 4 = 12\) - \(36 - 16 = 20\) - \(62 - 36 = 26\) These differences are: \[ 12, 20, 26 \] 5. **Identify the pattern**: The second differences seem to be increasing but not in a consistent manner. However, if we analyze the differences more closely, we can see that: - The first differences seem to be multiples of 4, except for the last difference (131). 6. **Check the last difference**: The last first difference (131) is not a multiple of 4. The previous differences (13, 17, 33, 69) can be analyzed further: - If we consider 64 instead of 62, we can check the pattern again: - If we replace 264 with 266, we can recalculate: - \(133 + 64 = 197\) - \(197 + 69 = 266\) 7. **Conclusion**: The odd one out in the series is 264, as it disrupts the pattern of differences. The correct number should be 266. ### Final Answer: The odd one out is **264**.

To find the odd one out from the series: 1, 14, 31, 64, 133, 264, we will analyze the differences between the consecutive terms to identify any patterns. ### Step-by-step Solution: 1. **Identify the series**: The given series is: \[ 1, 14, 31, 64, 133, 264 \] ...
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