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11.8, 11.9, 12, 12.3, 13.8, 24.4, 118....

11.8, 11.9, 12, 12.3, 13.8, 24.4, 118.8

A

11.9

B

11.8

C

12

D

24.4

Text Solution

AI Generated Solution

The correct Answer is:
To find the odd one out in the series: 11.8, 11.9, 12, 12.3, 13.8, 24.4, 118.8, we will analyze the differences between consecutive numbers and identify any irregularities. ### Step-by-Step Solution: 1. **Identify the series**: The given series is 11.8, 11.9, 12, 12.3, 13.8, 24.4, 118.8. 2. **Calculate the differences between consecutive terms**: - Difference between 11.9 and 11.8: \( 11.9 - 11.8 = 0.1 \) - Difference between 12 and 11.9: \( 12 - 11.9 = 0.1 \) - Difference between 12.3 and 12: \( 12.3 - 12 = 0.3 \) - Difference between 13.8 and 12.3: \( 13.8 - 12.3 = 1.5 \) - Difference between 24.4 and 13.8: \( 24.4 - 13.8 = 10.6 \) - Difference between 118.8 and 24.4: \( 118.8 - 24.4 = 94.4 \) 3. **List the differences**: - The differences are: 0.1, 0.1, 0.3, 1.5, 10.6, 94.4. 4. **Identify the pattern in differences**: - The first two differences are 0.1 (consistent). - The third difference (0.3) is three times the first difference (0.1). - The fourth difference (1.5) is five times the third difference (0.3). - The fifth difference (10.6) appears to break the pattern, as it is not consistent with the previous differences. 5. **Check if 24.4 is the odd one out**: - If we follow the pattern, the difference after 13.8 should be 10.5 (which is 7 times 1.5). - Therefore, the next number should be: \( 13.8 + 10.5 = 24.3 \). - The number in the series is 24.4, which is incorrect. 6. **Conclusion**: - The odd one out in the series is **24.4**. The correct number should be **24.3**.

To find the odd one out in the series: 11.8, 11.9, 12, 12.3, 13.8, 24.4, 118.8, we will analyze the differences between consecutive numbers and identify any irregularities. ### Step-by-Step Solution: 1. **Identify the series**: The given series is 11.8, 11.9, 12, 12.3, 13.8, 24.4, 118.8. 2. **Calculate the differences between consecutive terms**: - Difference between 11.9 and 11.8: ...
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